Ncert Maths Solutions
help me in mathematics {silly doubt}….how this 7th step come?
http://cbse.meritnation.com/img/curr/1/12/15/236/7736/NCERT_Solution_Math_Chapter_7_final_html_2aa04a39.gif
i m not able to understand how 6th step got reduces to 7th step…is it write?
n(n – 1)(2n – 1)/6n^2 = n/6 (n – 1)/n (2n – 1)/n = n (1 – 1/n) (2 – 1/n)/6
4/n (n(n – 1)/2 = (4n – 4)/2
Does that help?
Maths CBSE X 2008 set A Q.no. 1.10 mathguru solved board paper NCERT CBSE
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